Acceleration is the change in velocity over time. It is a vector quantity.
Porsche 911 can go from 0-60mph in 3 seconds. Our acceleration would be:
a = change in velocity / time = (60-0)/3 = 20 mph/s
Airbus A380 take off time and distance required
Let’s use an example for an Airbus.
The take-off velocity is 280km/hr
Acceleration is 1.0m/s/s or 1.0m/s2 (seconds squared)
How long does take off last?
First, we’ll have to do some simple unit conversion.
280km/hr = hour/seconds = 1 hour/3600 seconds
m/km = 1000m/1km
Now we can do our math.
= 280 * 1000 / 3600 = 78m/s
From this, we can see that it will take 78 seconds for take off to last
How long will the runway need to be in order to complete take off?
V(avg) = (v(final) + v(initial)) / 2 = 78m/s / 2 = 39m/s
Displacement = velocity * time = 39m/s * 78 seconds = 3042m
Our runway needs to be 3042 meters to take off!
What are velocity vs time graphs
The vertical axis represents the velocity of a object.
The slope represents the acceleration of the object. The value of the slope at a particular time represents the acceleration of the object at that instant.
The area underneath the slope represents the displacement of the object. To calculate this, we use a simple area formula: area = base * height.
What are acceleration vs time graphs
The vertical axis represents the acceleration of the object. At a particular time, you will get the acceleration of the object in meters per second squared for that moment.
The slope represents a quantity known as the jerk. The jerk is the rate of change of the acceleration.
Jerk = change in acceleration / change in time
The area underneath the slope represents the change in velocity.